(5x^2+19x+10)/(x+3)=0

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Solution for (5x^2+19x+10)/(x+3)=0 equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(5*x^2+19*x+10)/(x+3) = 0

5*x^2+19*x+10 = 0

5*x^2+19*x+10 = 0

DELTA = 19^2-(4*5*10)

DELTA = 161

DELTA > 0

x = (161^(1/2)-19)/(2*5) or x = (-161^(1/2)-19)/(2*5)

x = (161^(1/2)-19)/10 or x = (-(161^(1/2)+19))/10

(x+(161^(1/2)+19)/10)*(x-((161^(1/2)-19)/10)) = 0

((x+(161^(1/2)+19)/10)*(x-((161^(1/2)-19)/10)))/(x+3) = 0

( x+(161^(1/2)+19)/10 )

x+(161^(1/2)+19)/10 = 0 // - (161^(1/2)+19)/10

x = -((161^(1/2)+19)/10)

( x-((161^(1/2)-19)/10) )

x-((161^(1/2)-19)/10) = 0 // + (161^(1/2)-19)/10

x = (161^(1/2)-19)/10

x in { -((161^(1/2)+19)/10), (161^(1/2)-19)/10 }

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